Z$ = A$ + B$ < C$ + D$ = E < FThe expression is a perfectly valid integer expression, however, it is the wrong type for a string assignment. Previously, the error would have been “expected string expression” pointing at the = token (confusing). With the first operand implementation, the error will be pointing to the A$ token (good), in other words, the beginning of the numeric expression. Conceivably a better error might be “expected string operator or end-of-statement” pointing at the < token. But going with the “what is entered is what was intended” then the first operand implementation may be good enough.
The best course of action is to proceed with the first operand implementation and see what the results are.
One last action needs to be performed when operator tokens are received. In order to produce the correct error when a statement prematurely ends after an operator (when another operand is expected), the data type of a binary operator's second operand needs to be known. Therefore, before pushing an operator to the hold stack, the specific code of the operator will be determined based on the first operand, which will be on top of the done stack, and this code will be pushed to the hold stack. If an error occurs, the top of the hold stack can be checked to see what type of expression is expected to follow. (The find code routine with respect to operators, may need to be rewritten as a result of this change.)
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